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var middleNode = function(head) { // 经典使用快慢节点的方式解决 let fast = head; let slow = head; while(fast.next && fast.next.next) { fast = fast.next.next; slow = slow.next; } // 结尾的时候有可能刚好没值,也有可能是跨过一个才没值fast.next.next return fast.next ? slow.next : slow; };
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876. 链表的中间结点
思路——快慢节点
复杂度分析
The text was updated successfully, but these errors were encountered: