index.js

// Given an array nums of integers, return how many of them contain an even number of digits.


//     Example 1:

// Input: nums = [12, 345, 2, 6, 7896]
// Output: 2
// Explanation:
// 12 contains 2 digits(even number of digits). 
// 345 contains 3 digits(odd number of digits). 
// 2 contains 1 digit(odd number of digits). 
// 6 contains 1 digit(odd number of digits). 
// 7896 contains 4 digits(even number of digits).
// Therefore only 12 and 7896 contain an even number of digits.
//     Example 2:

// Input: nums = [555, 901, 482, 1771]
// Output: 1
// Explanation:
// Only 1771 contains an even number of digits.


//     Constraints:

// 1 <= nums.length <= 500
// 1 <= nums[i] <= 10 ^ 5

// Solution

const findNumbers = (nums) => {
    return nums.filter(el => el.toString().length % 2 == 0).length
};