Skip to content

Commit

Permalink
I don't prove that tsi is equal to tsi'
Browse files Browse the repository at this point in the history
  • Loading branch information
0xd34df00d committed Jan 20, 2021
1 parent 8850aee commit 7edda89
Showing 1 changed file with 1 addition and 1 deletion.
2 changes: 1 addition & 1 deletion tex/paper.mng
Original file line number Diff line number Diff line change
Expand Up @@ -582,7 +582,7 @@ with the corresponding proof terms referred in lemmas names.
Let $[[ empty |- es : ts ]]$ and $[[ es ]]$ be a value. In this case:
\begin{itemize}
\item if $[[ ts ]]$ is of the form $[[ (x : ts1) -> ts2 ]]$, then $[[ es ]]$ is of the form $[[ \ x : ts . es' ]]$,
\item if $[[ ts ]]$ is of the form $[[ < </ li : tsi // i /> > ]]$, then $[[ es ]]$ is of the form $[[ < l = es' > as < </ li : tsi // i /> > ]]$.
\item if $[[ ts ]]$ is of the form $[[ < </ li : tsi // i /> > ]]$, then $[[ es ]]$ is of the form $[[ < l = es' > as < </ li : tsi' // i /> > ]]$.
\end{itemize}
\end{lemma}
\begin{proof}
Expand Down

0 comments on commit 7edda89

Please sign in to comment.